# C Program to Read an Amount and Find Number of Notes

In this C program, we will split a given amount into currency notes.Starting from the highest denomination note, we will try to accommodate as many notes possible.

Let amount is A and current note is N, then number of notes is A/N and remaining amount is A%N.Let's say A = 450 and N = 100, then number of 100 notes is 450/100 = 4 and remaining amount is 450%100 = 50.
We will repeat this process for all notes in decreasing order.

## C program to accept an amount and find number of notes

```#include <stdio.h>

int main() {
int number, i;
int notes = {1000, 500, 100, 50, 10, 5, 1};
int noteCounter = {0};

printf("Enter a Number\n");
scanf("%d", &number);

for(i = 0; i < 7; i++) {
if(number >= notes[i]){
noteCounter[i] = number/notes[i];
number = number - noteCounter[i]*notes[i];
}
}

/* Print notes */
printf("Currency   Count\n");
for(i = 0; i < 7; i++){
if(noteCounter[i] != 0){
printf("%d  %d\n",notes[i],noteCounter[i]);
}
}
return 0;
}
```
Output
```Enter a Number
868
Currency   Count
500  1
100  3
50  1
10  1
1   3
```

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