- Write a program in Java to check for leap years.
- Algorithm to check whether a year is leap year or not.

A **leap year** contains 366 days instead of the usual 365, by extending February to 29 days rather than the common 28 days. A **leap year** is a year containing one additional day in order to keep the calendar year in sync with the astronomical year.

It takes the Earth approximately 365.242189 days – or 365 days, 5 hours, 48 minutes, and 45 seconds – to circle once around the Sun. However, the Gregorian calendar has only 365 days in a year, so if we didn't add a leap day on February 29 nearly every four years, we would lose almost six hours off our calendar every year.

Example of leap years: 1980, 1984, 1988, 1992, 1996

**Algorithm to check whether a year is leap year or not**

- If a year is divisible by 4 but not by 100, then it is a leap year.
- If a year is divisible by both 4 and by 100, then it is a leap year only if it is also divisible by 400.

if(((year%4 == 0) && (year%100 != 0)) || (year%400==0)){ /* Leap year */ } else { /* Not a leap year */ }

## Java Program to check whether for leap year

package com.tcc.java.programs; import java.util.*; public class LeapYearCheck { public static void main(String args[]) { int year; Scanner in = new Scanner(System.in); System.out.println("Enter a year"); year = in.nextInt(); if((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))) System.out.println(year + " is a Leap Year"); else System.out.println(year + " is not a Leap Year"); } }Output

Enter a year 2014 2014 is not a Leap Year

Enter a year 2012 2012 is a Leap Year