Here is a java program to find the area of a triangle using heron's formulae. Given the length of three sides of a triangle, we have to write a java program to find the area of given triangle. Given triangle can be either equilateral, isosceles, right angles triangle or scalene triangle.

Here we are going to calculate the area of triangle using Heron's Formula. Given length of three sides of a triangle, Heron's formula can be used to calculate the area of any triangle.

**Heron's Formulae**

Let X, Y and Z be the length of three sides of a triangle.

- Calculate the semi perimeter of the triangle as

Semi-Perimeter of triangle(S) = (X + Y + Z)/2 - Now, the area of triangle can be calculated as

Area of Triangle = √ S(S-A)(S-B)(S-C))

Let the length of three sides of triangle are 5, 10 and 7 meters. As per Heron's formulae, first of all we have to calculate it's semi-perimeter.

Semi-Perimeter(S) = (5+10+7)/2 = 11

Now, we can calculate area of triangle as

Area = √ 11(11-5)(11-10)(11-7)) = √ 264 = 16.24 m^{2}

## Java Program to Find Area of a Triangle

In this java program, we first take three integer input from user as the length of three sides of a triangle and store them in s1, s2 and s3 double variable. Then we calculate the area of given triangle using heron's formulae as mentioned above.

package com.tcc.java.programs; import java.util.Scanner; public class AreaOfTriangle { public static void main(String[] args) { double s1, s2, s3, area, S; Scanner scanner; scanner = new Scanner(System.in); // Take input from user System.out.println("Enter Three Sides of a Triangle"); s1 = scanner.nextDouble(); s2 = scanner.nextDouble(); s3 = scanner.nextDouble(); S = (s1 + s2 + s3) / 2; area = Math.sqrt(S * (S - s1) * (S - s2) * (S - s3)); System.out.format("The Area of triangle = %.2f\n", area); } }Output

Enter Three Sides of a Triangle 7 3 9 The Area of triangle = 8.79

Enter Three Sides of a Triangle 3 4 5 The Area of triangle = 6.00

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