In C++, the pointers to a structure variable in very similar to the pointer to any in-built data type variable. As we know that a pointer stores the address of a variable, a pointer to a structure variable stores the base address of structure variable.
Syntax for declaring a pointer to structure variable
struct structure_name *pointer_variable;
For Example :
struct Employee
{
char name[50];
int age;
float salary;
}employee_one;
struct Employee *employee_ptr;
To get the address of a structure variable, we can use addressOf operator(&).
struct Employee *employee_ptr = &employee_one;
To access the member variable using a pointer, we can use arrow operator(->). We can access member variable by using pointer followed by an arrow operator and then the name of the member variable.
employee_ptr->salary;
C++ Pointer to Structure Example Program
#include <iostream>
using namespace std;
struct employee {
char name[100];
int age;
float salary;
char department[50];
};
int main(){
struct employee manager, *ptr;
printf("Enter Name, Age, Salary and Department of Employee\n");
// Assigning data to members of structure variable
cin >> manager.name >> manager.age >> manager.salary >> manager.department;
/* Printing structure members using arrow operator */
ptr = &manager;
cout << "\nEmployee Details\n";
cout << "Name : " << ptr->name << "\nAge : "<< ptr->age << "\nSalary : "
<< ptr->salary << "\nDepartment : "<< ptr->department;
return 0;
}
Output
Enter Name, Age, Salary and Department of Employee Dan 42 8453 Accounting Employee Details Name : Aman Age : 42 Salary : 8453 Department : Accounting