Here is a Java Program to find the grade of a student, given the marks of N subjects. Given the marks of N subjects, we have to print the grade of a student based on the following grade slab.
- If Percentage Marks > 90, Grade is A+
- If 70 <= Percentage Marks <= 89, Grade is A
- If 60 <= Percentage Marks <= 69, Grade is B
- If 50 <= Percentage Marks <= 59, Grade is C
- If Percentage Marks <= 40, Grade is D
In this java program, we first ask user to enter number of subjects and store it in variable "count". Then using a for loop, we take marks of "count" subjects as input from user and add them to variable "totalMarks". Then we find the percentage marks of student using following expression assuming each subject is of 100 marks.
percentage = (totalMarks/(count*100)) * 100;Using a switch case, we check the grade of the student as per the slab mentioned above and print it on screen.
Java program to calculate the grade of a student
package com.tcc.java.programs;
import java.util.Scanner;
public class StudentGrade {
public static void main(String[] args) {
int count, i;
float totalMarks = 0, percentage, average;
Scanner scanner;
scanner = new Scanner(System.in);
System.out.println("Enter Number of Subject");
count = scanner.nextInt();
System.out.println("Enter Marks of " + count + " Subject");
for (i = 0; i < count; i++) {
totalMarks += scanner.nextInt();
}
System.out.println("Total MArks : " + totalMarks);
// Each subject is of 100 Marks
percentage = (totalMarks / (count * 100)) * 100;
switch ((int) percentage / 10) {
case 9:
System.out.println("Grade : A+");
break;
case 8:
case 7:
System.out.println("Grade : A");
break;
case 6:
System.out.println("Grade : B");
break;
case 5:
System.out.println("Grade : C");
break;
default:
System.out.println("Grade : D");
break;
}
}
}
Output
Enter Number of Subject 5 Enter Marks of 5 Subject 45 69 53 58 62 Total MArks : 287.0 Grade : C
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