C program to check whether a number is odd or even without using if else statement

  • How to check whether a number is odd or even without using if else statement in one line.
  • Write a program in C to check a number is odd or even.

Required knowledge: Bitwise operator.
Algorithm to check odd and even number using bitwise operator
  • Check whether least significant bit of a number(N) is 0 or not by doing bitwise And(&) with 1. if (N & 1) == 0, that means N is even otherwise odd number.

C program to check odd or even number using bitwise operator

#include<stdio.h>

int main() {
    int n;
    
    printf("Enter a number\n");
    scanf("%d", &n);
    
    (n & 1 && printf("Odd"))|| printf("Even");
    
    return 0;
}
Output 
Enter a number
3
3 is Odd

Enter a number
12
12 is Even

C program to check odd or even number using bitwise operator

Algorithm to check odd and even number using bitwise operator
  • If input number(N) is divisible by 2(N%2 == 0) then N is even otherwise odd number.
#include<stdio.h>

int main() {
    int n;
    char *strList[] = {"Even", "Odd"};
    
    printf("Enter a number\n");
    scanf("%d", &n);
    
    printf("%d is %s", n, strList[n%2]);
    
    return 0;
}
Output 
Enter a number
5
5 is Odd

Enter a number
8
8 is Even
Posted by
Labels: ,