Returning Pointer from Function in C++

In C++ programming language, we can return a pointer from a function like any other data type. We have to declare return type of the function as pointer.

For Example :
int* getEvenNumbers(int N){
/* Function Body */
Points to Remember
As we know that, local variables gets created when control enters a function and gets destroyed as soon as control exits from a function. We should not return pointer to a local variable because as soon as control returns from a function the memory pointed by pointer no longer contains data of local variable.

If we want to return pointer to a local variable then we should declare it as a static variable so that it retains it's value after control exits from function.

C++ Program to return a pointer from a function

#include <iostream>
using namespace std;
// This function returns an array of N odd numbers
int* getOddNumbers(int N){
    // Declaration of a static local integer array 
    static int oddNumberArray[100];
    int i, odd = 1;
    for(i=0; i<N; i++){
        oddNumberArray[i] = odd;
        odd += 2;
    // Returning base address of oddNumberArray array
    // As oddNumberArray is a static variable, it will 
    // retain it's value even after function exits 
    return oddNumberArray;
int main(){
   int *array, counter;
   array = getOddNumbers(10);
   cout << "Odd Numbers\n";
   for(counter=0; counter<10; counter++){
       cout << array[counter] << " ";

   return 0;

Odd Numbers
1 3 5 7 9 11 13 15 17 19